Question

an object has a velocity V= 2i + 4 j metre per second at time t =0 . it undergoes a constant acceleration a= i -3j m/s^2 for 4s then the coordinates of the object if it is at origin at t=0 is????

Answer 1

Answer:

(16, -16)

Explanation:

a) velocity in x direction = +2m/s

b) velocity in y direction =+4m/s

c) acceleration in x direction =1m/s²

d) acceleration in y direction = -3m/s²

Now lets deal with individual direction

Distance covered in 4 second

1) in x-direction = s= ut + 1/2at²

                             s= 2*4 + 1/2*1*4*4

                             s = 16m

2) in y direction = s= ut + 1/2at²

                            s = 4*4 + 1/2*(-3)*4*4

                           s = -16 m

therefore coordinate in 4 second is = (16, -16)