Question

An object has an acceleration of 6.0 metre per second square if mass of this object where tripled with no change in its net force then its new acceleration would be blank metre per second

Answer 1

Given :

✴ First case :

▪ Accleration of object = 6m/s²

▪ Applied force = F

▪ Mass of object = m

✴ Second case :

▪ Applied force = F

▪ Mass of object = 3m

To Find :

▪ Acceleration of an object in second case.

Concept :

➡ This question is completely based on the concept of Newton's second law of motion.

➡ As per this law, Force is defined as the product of mass and acceleration.

➡ Force is a vector quantity.

➡ It has both magnitude as well as direction.

Mathematically,

$\bigstar\:\underline{\boxed{\bf{\large{\pink{F=m\times a}}}}}$

Calculation :

$\dashrightarrow\tt\:F_1=F_2\\ \\ \dashrightarrow\tt\:m_1a_1=m_2a_2\\ \\ \dashrightarrow\tt\:(m)(6)=(3m)(a_2)\\ \\ \dashrightarrow\tt\:a_2=\dfrac{6}{3}\\ \\ \dashrightarrow\underline{\boxed{\bf{\large{\blue{a_2=2\:ms^{-2}}}}}}\:\orange{\bigstar}$

Answer 2

Given :

↗ Acceleration of an object = 6m/s²

To Find :

↗ New acceleration of an object if mass of this object increased by factor 3.

[Applies force is same in both cases.]

Solution :

❇ As per Newton's second law of motion, Relation b/w applied force, mass and acceleration is given by

$\orange{\circ}\:\boxed{\bf{\red{F=ma}}}$

ATQ,

$\twoheadrightarrow\rm\:F_1=F_2=F\\ \\ \twoheadrightarrow\rm\:m_1a_1=m_2a_2\\ \\ \twoheadrightarrow\rm\:a_2=\dfrac{m_1a_1}{m_2}\\ \\ \twoheadrightarrow\rm\:a_2=\dfrac{\cancel{m}\times 6}{3\:\cancel{m}}\\ \\ \orange{\twoheadrightarrow}\underline{\boxed{\bold{\rm{\green{a_2=2\:ms^{-2}}}}}}\:\blue{\clubsuit}\\ \\ \bigstar\:\purple{\mathfrak{\large{Be\:Brainly}}}$