Question

An object has an acceleration of 8 m/s^2. if the net force acting on the object is increased by a factor 2 and its mass is decreased by a factor of 2, What would its new acceleration be ? Pls answer fast. ( Who ever write the correct solution for the given answer quickly will be marked as the brainliest answer.. hurry up.It is urgent. Hint- the answer is 32 m/s^2

Answer 1

Answer:

32m/s^2

Explanation:

as F=ma

$F_1=m_1 a_1=8m_1\\F_2=m_2a_2\\so\\2F_1=\frac{m_1}{2} a_2\\2(8m_1)=\frac{m_1}{2} a_2\\2*2(8m_1)={m_1} a_2\\a_2=32$

Answer 2

Given

Acceleration of an object = 8 m/s²

Condition applied

• force is doubled . (F' = 2F)
• mass is halved. ( m' = m/2)

To Find

new acceleration (a').

Formula

:- F = ma

Calculations

F = ma

=> a = F/m = 8 m/s² ( Given )

Now,

a' = F'/m'

= 2F/0.5m

= 4 F/m = 4 × 8 = 32 m/s² (Since, F/m = 8 m/s²).

Hence, new acceleration of the body is 32 m/s²