An object has initial velocity vo = 2i ms-1. It is given an acceleration a = 2i-3j ms-2. Its speed after 1 second will be
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Given : An object has initial velocity vo = 2i ms-1.
It is given an acceleration a = 2i-3j ms-2.
To Find : Its speed after 1 second
Solution:
V = U + at
U = initial velocity = 2i m/s
a = acceleration = 2i-3j m/s²
t = time = 1 sec
V = final velocity ( here velocity after 1 sec)
V = 2i + (2i - 3j)(1)
=> V = 2i + 2i - 3j
=> V = 4i - 3j
Speed = √4² +(-3)² = √16 + 9 = √25 = 5 m/s
speed after 1 second is 5 m/s
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