Question

An object has moved through a distance. can it have zero displacement? if yes, support your answer with an example​

Answer 1

Answer:

Yes, the object instead of moving through a distance can have zero displacement. Example: If an object travels from point A and reaches to the same point A, then its displacement is zero.

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Answer 2

$\setlength{\unitlength}{1.2mm}\begin{picture}(8,2)\thicklines\put(15,6){\line(0,1){50}}\multiput(15,6)(0,1.5){33}{\line(1,2){1.8}}\put(12,30){\vector( - 4,0){65}}\put(12,30){\vector(4, - 0){0.3}} \put( -55,6){\line(0,1){50}}\multiput( - 56.8,4.8)(0,1.5){33}{\line(1,2){1.8}} \qbezier( -8,30)( -8 ,30)(15,55)\qbezier( -35,30)( - 35 ,30)( - 55,55)\put( - 8, 30){\vector(0,1){22}}\put( - 35, 30){\vector(0,1){22}}\put( - 20, 30){\vector(0, - 1){15}}\put( - 22,28){\vector( - 1,0){11.5}}\put( - 22,28){\vector(1,0){1}}\qbezier( - 4,34)( - 6,36)( - 8,34)\qbezier( - 35,34)( -35,35)( - 38,34)\qbezier( - 55,50)( -53,48)( - 52,52)\qbezier(15,50)(12,48)(12,52)\put( -$ 29,25){ \sf{d}}\put( - 19,16){ \sf{w}}\put( - 49,26){ \sf{$ \sf T_1 Sin\:37^\circ$}}\put( - 2,26){ \sf{$ \sf T_2 Sin\:53^\circ$}}\put( - 54.5,47){ \sf{$ \sf 37^\circ$}}\put( 10,47){ \sf{$ \sf 53^\circ$}}\put( - 39.5,36){ \sf{$ \sf 37^\circ$}}\put( -7.9,36){ \sf{$ \sf 53^\circ$}}\put( - 40,54){ \sf{$ \sf T_1 cos\:37^\circ$}}\put( -13,54){ \sf{$ \sf T_1 cos \: 53^\circ$}}\end{picture}