Question

An object having a mass 'm' moving with velocity 'v' possess a kinetic energy 'k'.if its velocity is doubled, it's kinetic energy will become

Answer 1

Answer: ...will become 4 times

Explanation:

Let the initial kinetic energy be $k_1$ and the final kinetic energy for twice the velocity be $k_2$

Here velocity(v) is doubled so it became 2v.

$k_1=\frac{1}{2} mv^{2}$

Putting 2v instead of v will represent the velocity is doubled.

$k_2=\frac{1}{2} m(2v)^{2} \\k_2=\frac{1}{2} m*4v^{2} \\k_2=4*\frac{1}{2} mv^{2} \\k_2=4*k_1$

Now we can clearly see that if the velocity become twice its original value, the final kinetic energy will become 4 times the original.