Physics, asked by sen65, 1 year ago

an object having a velocity 4.0 M per second is accelerated at the rate of 1.2 M per second square for 5.0 seconds find the distance travelled during the period of acceleration

Attachments:

Answers

Answered by HeManShow
1
Velocity increased in 5 seconds 1.2×5
=6m/s
displacement=velocity ×time
=6×5
=30metres

Hope it helped please mark as the Brainliest
Similar questions
Math, 6 months ago