Question

An object having a velocity of 4m/sec is accelerated at the rate of 7.2m/sec^2 for 10 sec find the distance.​

Answer 1

Answer:

400m

Explanation:

Please find the explanation attached.

Thanks

Answer 2

Answer:

400 m

Explanation:

According to the given question,

u = initial velocity = 4 m/s

a = acceleration = 7.2 m/s^2

t = time = 10 sec

And we are asked to find distance.

We know,

• s = ut +1/2 at^2

By putting the values we get,

• s = 4×10+1/2 × 7.2 × 100

• s = 40 + 360

• s = 400 m

Here in this question displacement = distance as the direction is not changing.

Thus 400m is the distance ans.