Question

an object having a velocity of an 40m/sec2 is accelerated at a rate of 1.2m/sec2 for 5.0sec. find the distance traveled during the time of acceleration​

Answer 1

use second equation of motion in a straight line: s= ut + 1/2(a)(t)^2

where u,a and t are known and s=?

so, by this s= 215

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Answer 2

Answer:

Answer in photo

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Explanation:

On putting the values of initial velocity, accelaration and time taken, we can find the distance covered during that time.