Question

An object having an uncertainty in momentum of 6.66 x 10-10Kgm/s will have an uncertainty in position of (Planck's constant is 6.626 x 10-3mKg/s) plx help​

Answer 1

Explanation:

v = 40m/s, m = 9.1×10−31 kg, h = 6.626×10−34 Js and Δp = P×10−6

We know that, P = m×v

P = 9.1×10−31×40 = 364×10−31 kgm/s

Δp = 364×10−37

Heisenberg Uncertainty principle formula is given as,

\Delta\, \times \Delta p\geq\, \frac{h}{4\pi }

\Delta\, \times\, \geq \, \frac{h}{4\pi \Delta p}

\Delta\, \times\, \geq \, \frac{6.626\times 10^{-34}}{4\times 3.14\times364\times 10^{-37} }\, =1.44m