Question

An object having height of 5 cm is placed at 30 cm in
front of concave lens having focal length of 20 cm. Find
the position, nature and size of an image.​

Answer 1

Height of object,   , object distance  , focal length  

Now, from mirror formula :  

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

$= \frac{-1}{20} + \frac{1}{30}$

$= \frac{-1}{60}$

$v$ $=-60 cm$ $_$- image distance

Magnification, $m$ $= -\frac{v}{u} = -\frac{-60}{-30} = -2$

Size of image, $h_{1}$ $= m(h_{o} )$ $= -2(5)$ $= -10$

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