An object having mass 3 kg at rest moves under the action of a forcefor 4s with an acceleration of 2.5m/s2. What is the gain in the momentum of the object?
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Answer:= m×a=10×2=20 N
Explanation:Mass of the body =10 kg
Initial velocity u=4 m/s
Final velocity v=8 m/s
Time t=2s
a) Momentum before force acts p
1
=m×u=10×4=40kg.m/s
b) Momentum after force acts p
2
=m×v=10×8=80kg.m/s
c) Gain in momentum per second =
2
40
=20kg.m/s
d) Acceleration a=
t
v−u
=
2
8−4
=2m/s
2
Force =m×a=10×2=20 N.
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