an object having mass of 2 kg is allowed to fall from a height of 500 m under the effect of gravity then calculate the time it just reaches the ground
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They both meet the ground at the same instant. It isn't the acceleration that differs because the mass of the earth has not changed significantly. Only the force between the balls will be different. That is to say, one will be much more difficult to stop from falling.
Imagine a semi truck and a sports car moving at the same speed (or accelerating). Same deal. They both move at the same pace but one will require far more force to move.
Imagine a semi truck and a sports car moving at the same speed (or accelerating). Same deal. They both move at the same pace but one will require far more force to move.
different29:
my question was to calculate there was no comparison between the two bodies there was only one object which was having a mass of 2kg
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as mass is not considerable during free fall every object of any mass fall with the same acceleration
s=ut+1/2at^2
here s=500m
a=10ms^-2 and u=0ms^-1
t=?
putting the value
500=0+1/2×10×t^2
solving for t we get
t=10s
s=ut+1/2at^2
here s=500m
a=10ms^-2 and u=0ms^-1
t=?
putting the value
500=0+1/2×10×t^2
solving for t we get
t=10s
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