Question

An object having total volume of 10 m is floating
and it is just completely immersed in a fluid of
density 0.5 g/cc. Buoyant force acting on the
object is (g = 10 m/s2)
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Answer 1

Answer:

buoyant force=VsPg

=10*1000*10

=100000 newton

Explanation:

Answer 2

Buoyant force acting on the object = 50N.

Here, according to the given information, we are given that,

An object is provided and it has a total volume of 10 m³. This given object is them immersed in a fluid which has a density of 0.5 g/cc.

Now, the Buoyant force acting on the object can be found out by multiplying the volume of the body submerged in the fluid with the density of the given fluid and the gravitational acceleration acting on it.

Then, by utilizing this formula to find the Buoyant force acting on the object, we get,

Buoyant force acting on the object = $(10).(0.5).10$, where the acceleration due to gravity is shown here has 10 m/s².

Then, we get, Buoyant force acting on the object = 50N.

Hence, the Buoyant force acting on the object = 50N.

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