An object is 15 cm away from a converging lens of focal length 10 cm. If it is placed then its image is formed on the screen. A diverging lens is placed in contact with the converging lens and due to this the screen has to be retracted 30 cm to obtain a clear image again. The focal length of the diverging lens
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Answer:
Given: f=−15
v=−10
From mirror formula, v1−u1=f1
−101−u1=−151
u1=151−101
u=−30 cm
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