Question

An object is 20cm infront a
convex Mirror. If the image
height is 1/5 times of the object
height Determine
a. Focal length b. Image height
c. properties of Image​

Answer 1

Answer:

u= -20cm

-v/u = hi/ho

-v/u = 1/5

-v/-20 = 1/5

v= 20/5 = 4 cm

1/v + 1/u = 1/f

1/4 +  1/-20 = 1/f

a) f= 5 cm

c) Diminished, virtual and erect

note: image height cannot be determined with the information provided (either of the value should be given)