An object is 30 cm fro spherical mirror , along the central axis , The absolute value of lateral magnification is 1÷2 . The image produced is inverted , What's Focal lenght ??
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Heya......!!!
Image is inverted , so it is real . u and v both are negative . Magnification is given = 1/2 .
Therefore , v = u/2
Given , u = -30 cm and v = -15 cm .
Using Mirror's formulae ,,
1/v + 1/u = 1/f
We have
1/f = 1/-15 - 1/30 =>>>> -1/10
Focal length of mirrors =» -10 cm .
Hope it helps u :-)
Image is inverted , so it is real . u and v both are negative . Magnification is given = 1/2 .
Therefore , v = u/2
Given , u = -30 cm and v = -15 cm .
Using Mirror's formulae ,,
1/v + 1/u = 1/f
We have
1/f = 1/-15 - 1/30 =>>>> -1/10
Focal length of mirrors =» -10 cm .
Hope it helps u :-)
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0
Answer:
answer is -10cm..........
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