an object is a 1.5m from a mirror which forms an errect image one-fourth[exactly]the size of the object determine the focal length of the mirror.so what type of mirror is it
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nikhil575532
21.02.2019
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An object is 2m from a lens which forms an erect image 1/4th the size of the object. Determine the focal length of the lens,what type of lens is this
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Distance of the object , u = - 2 m
Magnification , m = 1/4
let distance of image be v m
and focal length be f m
As we know ,
m = v/u
1/4 = v/2 (substitute the value of u & m)
so, v = -2 /4 v =-1/2 ,v = - 0.5 m
Lens formula,
1/f = 1/v-1/u
1/f = -1/0.5 -(-1/2)
= -1/0.5+1/2
= (-2+0.5)/0.5 × 2 (LCM of 0.5 and 2)
= -1.5/1
1/f = -1.5 /1
f = -1/1.5
f = -0.67 m
The image is small , erect, Therefore , it is a concave len.
Explanation:
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