An object is acted upon by two forces 3newton and 5mewton, inclined at 60degrees to each other.if the object is moved through a distance of 6meters by a resultant F.what will be the work done by the force.
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As the two force quantities are vevtors, so we will add them through vector law of addition.
Resultant vector= under root a^2 +b^2 +2abcostheta
Since the angle between them is 90 (cos90=0)
Resultant vector = under root a^2 +b^2
a=3N. b=4N
Resultant vector = 5N (magnitude
i think this is correct
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