Question

an object is an object is dropped at a height 500 metre calculate its velocity​

Answer 1

intial velocity = 0

acceleration = 10 m/s^2

final velocity = ?

using second equations of motion.

v^2-u^2 = 2as

v^2 -. 0 = 2×10×500

v^2 = 10000

v = 100m/s.

it's velocity =100m/s.

Answer 2

Answer:

Since the body is falling freely ,

Its initial velocity = 0

given ,

H = 500 m

[ Note : when an object falls freely , its acceleration will remain constant . The value of acceleration will be equal to the value of acceleration due to gravity. The value is 9.8 m/s² but if they give the value of g as 10 m/s² , dont use 9.8 m/s² as the value and vice - versa ]

H = ut + 1/2at²

   = 1/2gt²

500 = 1/2×10×t²

5t² = 500

t² = 500 / 5

   = 100

t = √100

 = 10 s

the velocity on reaching the ground is given by,

v = u+at

v = gt

  = 10×10

  = 100 m/s

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