Science, asked by hguii, 11 months ago

An object is at a distant of 19 cm from a concave mirror and the image has formed on itself. Find the magnification of the image and the size of the image. Full detailed explanation is required. No spam or copied answer is allowed.

Answers

Answered by Anonymous
21

It is given that,

The distance of the object (u) = 19 cm

The distance of the image (v) = 19 cm

Let, the focal length be, 'f' and the magnification be, 'm'

From the relationship we know that,

m = \frac{-v}{u}

or, m = \frac{-19}{19} \\or, m = -1\\

So, the magnification is -1.

∵ It should be noted that while the magnificent is negative then the formed image is real. So, real image should be formed.

We know that,

Size of the image = (u*v)\\= (19)*(-1)\\= - 19 cm

So, the size of the formed image is -19 cm.

∵ For the size of the mirror,

We know that,

\frac{1}{f} = \frac{1}{u}+\frac{1}{v}   \\or, \frac{1}{f} = \frac{1}{19} + \frac{1}{19}\\ or, \frac{1}{f} = (\frac{1+1}{19}) \\or, \frac{1}{f} = \frac{2}{19} \\or, f = \frac{19}{2} \\or, f = 9.5 cm

So, the length of the mirror is 9.5 cm.

Answered by Anonymous
21

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https://brainly.in/question/8969234

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