An object is at a height 10 cm from the surface of water of refractive index = 4/3. An observer sees the object from a position inside water. The apparent height of the object from the surface of the water is
(1) 7.5 cm
(2) 13.33 cm
(3) 10 cm
(4) 1 cm
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Answer:
Given, μ=
3
4
,height=10cm
So, from the figure it is clear that object appears to be raised by the
4
10
cm=2.5cm
So the distance between the mirror and O' is: 5+7.5=12.5cm
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