Question

An object is at rest when it undergoes a constant acceleration of 13 m/s2 for 5.0 seconds. How far will it have traveled during this time?

Answer 1

Answer:

162.5m

Explanation:

s = ut + 1/2 at^2

= 0×5 +1/2 × 13 × 5^2

= 1/2 × 13 × 25

= 162.5 m

Answer 2

Answer:

162.5

Explanation:

u=o m/s

a = 13m/s

t =5.0 seconds

s=ut+1/2 at^2

0 × 5 +1/2 ×13 ×5^2

1/2 ×13 ×25

162,5