An object is at the distance 20cm from covex lens of focal length 10cm .find image distance and nature of the image
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Given,
u = 10 cm
The object is placed before the lense so we will put negitave sign.
f = 20 cm
We will take it as a positive because the focal length is always positive.
Formula we will use here:-
1/f = 1/v-1/u
=> 1/20=1/v-1/-10
1/v= 1/20+1/10
1/v=1/20-1/10=1/-20
v= -20
We got the value of we which is -20.
The formation of the image is on the attached sheet.
The object is between the lens and the image, show the image can be virtual. The image and . Object vote are above the principal axis . so we can say that the image is erect.
We found that the images is :-
- virtual
- erect
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