an object is brought from a tower 180m high. how long does it take to reach the ground (take g=10m/s)
Answers
Answered by
1
t={2h/g}^1/2
{2*180/10}^1/2
=6 sec.
{2*180/10}^1/2
=6 sec.
Answered by
1
u = 0
g = 10 m/s^2
S = 180m
t = ?
v =?
Using S = ut + 1/2at^2
180=1/2×10×t×t
360 = 10t^2
36 = t ^2
{t = 6sec}
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