Physics, asked by xenehmukando, 2 months ago

An object is constrained by a cord to move in a circular path of radius 0.5m on a horizontal frictionless surface. The cord will break if its tension exceeds 16N. The maximum kinetic energy the object can have is

Answers

Answered by nirman95
37

Given:

An object is constrained by a cord to move in a circular path of radius 0.5m on a horizontal frictionless surface. The cord will break if its tension exceeds 16N.

To find:

Max kinetic energy of object ?

Calculation:

Let velocity of the object be v :

So, max tension should be 16 N equal to its centrifugal force at critical conditions.

 \sf \therefore \:  f_{c} = 16

 \sf \implies \: \dfrac{m {v}^{2} }{r}  = 16

 \sf \implies \: m {v}^{2} = 16  \times r

 \sf \implies \: \dfrac{1}{2}  m {v}^{2} = 8 \times r

 \sf \implies \ KE_{max} = 8 \times r

 \sf \implies \ KE_{max} = 8  \times 0.5

 \sf \implies \ KE_{max} = 4 \: joule

So, max kinetic energy is 4 Joule

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