An object is displaced from positin vector r_1=(2hati+3hatj) m to r_2=(4hati+6hatj) m under a forc F=(3x^2hati+2yhatj)N Find the work done by this force.
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The answer should be
Work done=6x^2+ 6y
Given,
r1= 2i+3j and r2= 4i+6j
We know, displacement between the two position vectors will be,
d= r2-r1
= (4i+6j) - (2i-3j)
=2i+3j
Force given,
F= 3x^2+2yj
Therefore,the work done will be,
W=F.d
=(3x^2+2yj)(2i+3j)
=6x^2+6y
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