Question

an object is dropped at a height 500 metre calculate its velocity​

Answer 1

Answer:

Explanation:

the distance is ie. s = 500 m

Taking u = 0 m because the object is dropped and not thrown and g = 10 m/s^-2 it is along the direction of gravitational acc.

Now , applying the values in the eq,

s = ut + 1/2 at^2

500 = 0 + 1/2*10*t^2

t=10 s

v = final - initial position / final t - initial t

= 500/10 m/s

=50 m/s