Physics, asked by 105604, 6 hours ago

an object is dropped from a 32m tall building. How fast will it be going when it strikes the ground?

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Answered by Itsmeyourfriend
1

Answer:

If there is no air resistance, the energy formula is v = sqrt(2*g*h)

If there is no air resistance, the energy formula is v = sqrt(2*g*h)where v = velocity, h = distance dropped, g = gravitational constant, and m = meters , in this case

If there is no air resistance, the energy formula is v = sqrt(2*g*h)where v = velocity, h = distance dropped, g = gravitational constant, and m = meters , in this casev = sqrt(2*(9.8m/sec2)*32m) = sqrt(627.2 m2/sec2) = 25.04 m/sec when it hits the ground

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