Question

An object is dropped from a certain height after 2 second the velocity of the object will be

Answer 1

Answer:

19.6 m/s

Explanation:

Use equation of motion

• v = u + at

Where

• v = Velocity after time t
• u = Velocity when t = 0 (aka initial velocity)
• a = Acceleration of body
• t = Time after which velocity changed from u to v

It's given that the object is dropped. It means ovjects' initial velocity (u) is zero. Also, acceleration of object is due to earth's gravity. It is 9.8 m/s² downwards

v = u + at

= 0 m/s + (9.8 m/s² × 2 s)

= 19.6 m/s

Answer 2

Let h be the height of the object.

By Newton's 2nd law of kinematics,

s = ut + 1/2 at^2

h = 0×1 + 1/2 × 10 × 1^2

h = 5 m

When there's no gravity, velocity of throwing object need to be -

v = h / t

v = 5 / 1

v = 5 m/s

Therefore, the object need to be thrown with velocity of 5 m/s.