an object is dropped from a certain height. after 2 seconds the velocity of the object will be ( take g=9.8 metre per second square)
a.19.6 m/s
b.9.8 m/s
c.4.6 m/s
d.0m/s
Answers
Answered by
10
Answer:
(a)
v=u+at
v=0+9.8×2
v=19.6m/s^2
Answered by
19
Given:-
☆Initial velocity(u)=0 (as it was at rest initially)
☆Acceleration due to gravity(g)=9.8m/s²
☆Time(t)=2s
To find:-
☆Velocity of the object after 2s(v)
Solution:-
By,using the 1st equation of motion,when u=0,we get-----
=>v=gt
=>v=9.8×2
=>v=19.6m/s
Thus,velocity of the body after is 2s is 19.6m/s and hence correct option is (a).
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