Question

an object is dropped from a height h when will it have maximum potential energy and kinetic energy

Answer 1

Maximum potential energy is based on height.
The higher you are, the greater is the potential energy.
Therefore, max potential energy = mgh
as h will be the highest point

The speed of the object increases as the object comes down.
Therefore, the object's max speed will be just the moment before it touches the ground.
for this case, displacement = h metres
initial velocity = 0 m/s
Acceleration due to gravity = g
using 3rd equation of motion
v²-u²=2as
v²-0²=2gh
v²=2gh
$v = \sqrt{2gh}$
Kinetic energy is max when speed is max
Therefore max kinetic energy =
$\frac{1}{2} m {v}^{2}$
$= \frac{1}{2} m { \sqrt{2gh} }^{2}$
$= mgh$
Hope it helps
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Answer 2

Answer:

The object will have its most potential energy when it is positioned at a height of h, and it's highest kinetic energy when it is dropped from that height just before it touches the ground.

Explanation:

• The object has the most gravitational potential energy and zeroes kinetic energy when it is kept at a height h. Because the highest amount of energy that can be converted into other forms is called potential energy. You need more energy to move the thing at a higher altitude. Therefore, potential energy grows along with the height and is maximum at the maximum height of an object.
• The body has its highest kinetic energy and zeroes potential energy while it is being lowered to the ground. Since the mass is fixed, an increase in velocity inevitably results in an increase in kinetic energy

Thus, The object will have its most potential energy when it is positioned at a height of h, and its highest kinetic energy when it is dropped from that height just before it touches the ground.

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