Question

an object is dropped from a height of 100m its velocity at the moment it touches the ground is​

Answer 1

Answer:

20√5m/s

Explanation:

u = 0m/s

s = 100m

a = g = 10m/s^2

v = ?

By applying 3rd equation of motion

i.e. v^2 = u^2 + 2as

we get,

v^2 = (0)^2 + 2(10)(100)

v^2 = 2000

v = √2000

v = 20√5m/s