Question

An object is dropped from a height of 120m. Acceleration is 10m/s. Find the distance traveled by object after 1s, 2s, 3s. What is final velocity of object after 3s

Answer 1

Answer:

Explanation:

s = ut+1/2*a*t*t

The Object Is Dropped Hence Initial Velocity = 0

s = 1/2*10*t*t = 5*t*t

(a) Distance Travelled After 1 second = 5*1*1 = 5 m

(b) Distance Travelled After 2 Second = 5*2*2 = 20 m

(c) Distance Travelled After 3 Second = 5*3*3 = 45 m

(d) Velocity After 3 Second

v = u+at

again Initial Velocity = 0

v = at

v = 10*3 = 30 m/sec