An object is dropped from a height of 80 m. It will remain in air for time [Take g=10 m\s²]. Plz explain with step
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Height = 80m
initial velocity = 0 m/s ( dropped )
h = 1/2 × g × t^2
80 = 1/2 × 10 × t^2
t^2 = 16
t = 4s
It will remain in air till 4s.
initial velocity = 0 m/s ( dropped )
h = 1/2 × g × t^2
80 = 1/2 × 10 × t^2
t^2 = 16
t = 4s
It will remain in air till 4s.
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