An object is dropped from a height of 80m it will remain in air fir time g=10m/second square
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Answered by
37
h = 80m
g= 10 m/s sq.
s= ut + 1/2 at²
80= (0)t + 1/2×10×t²
80×2/10 = t²
t² = 16
t = 4sec.
g= 10 m/s sq.
s= ut + 1/2 at²
80= (0)t + 1/2×10×t²
80×2/10 = t²
t² = 16
t = 4sec.
Answered by
12
T = √(2h / g)
= √(2 × 80 m / 10 m/s²)
= √(16)
= 4 seconds
Object will remain in air for 4 seconds
= √(2 × 80 m / 10 m/s²)
= √(16)
= 4 seconds
Object will remain in air for 4 seconds
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