Question

An object is dropped from a height of120m the acceleration of the object is10ms2 fownards find the distance by theobject after 1s 2s 3s. what ia the final velocityof the object after 3s​

Answer 1

Answer:

Initial difference in height = (150 - 100)m = 50 m We know that, by second equation of kinematics, s = ut + 12at2 considering g = 10 m/s Distance travelled .