An object is dropped from a tower that is 180 m tall how long it will take to reach ground
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u=0
a=9.8m/s^2
s=180m
s=ut+1/2at^2
-180= -1/2*9.8t^2
-180= -4.9t^2
t^2 = -180/-4.9
t^2=36.73
t=6.06 seconds
therefore time taken by the object to reach the ground is approx 6 seconds
a=9.8m/s^2
s=180m
s=ut+1/2at^2
-180= -1/2*9.8t^2
-180= -4.9t^2
t^2 = -180/-4.9
t^2=36.73
t=6.06 seconds
therefore time taken by the object to reach the ground is approx 6 seconds
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