Question

An object is dropped from an aircraft when it is directly above the target at a height of 1000m. The aircraft is moving with a horizontal velocity of 500km/hr. Will the object hit the target? If not, by how much distance will the object miss the target?​

Answer 1

Answer:

it will miss the target

Explanation:

Since the the aeroplane is directly above a target at a height of 1000 m, the distance by which bomb will miss the target is equal to the horizontal distance covered by bomb during its fall

Horizontal distance (d)= Time of fall × Horizontal speed

⇒d=t×v

⇒d=

g

2h

×500km/h

⇒d=

10

2×1000

×500×

18

5

m/s

⇒d=1964.2m

Answer 2

Answer :

To find : aircraft is moving with speed of  500km/hr. It drops object from  height of 1000m on target we have to find if object will miss the target or not.

Given : horizontal velocity of aircraft = 500km/hr.

            height of aircraft from target = 1000m

As we know, Free fall of object.

         $h = \frac{1}{2}gt^{2}$

         $t = \sqrt{\frac{2h}{g} }$      

where, g = acceleration due to gravity

           h = height travelled = 1000m

          t = time taken

Since the aircraft is directly above a target at a height of 1000m, the distance by which object will miss the target is equal to the horizontal distance covered by object during its fall.

hence , $= \sqrt{\frac{2\times 1000}{10} } \times 500 \times\frac{5}{18} m/s$    

on solving we get,

   $= 1964.2 m$.

hence by distance of 1964.2m object from aircraft will miss the target.