An object is dropped from cliff fall from acceleration 10m/sec^2 . find its speed 2s after it was dropped?
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initial speed(u) = 0
final speed = v
time = 2 s
so acceleration = (v-u)/t
10 = (v-0)/2
v = 10*2
so speed after 2 s = 20m/s
final speed = v
time = 2 s
so acceleration = (v-u)/t
10 = (v-0)/2
v = 10*2
so speed after 2 s = 20m/s
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