an object is dropped from height. it was thrrough a distance of 24.5 m in the last second before hitting ground. find the height from which it was dropped.
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S(t)=1/2at^2=h
S(t-1)=1/2a(t-1)^2
where a=g=10
given S(t)-S(t-1)=24.5
on solving we get t=2.95
therefore,h=43.5m
vivekstar:
thanks but this is not answers
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