Question

An object is dropped from height of 120m.The acceleration of the object is 10ms-2 downwards. Find the distance travelled and velocity after 3 sec.

Answer 1

The final velocity is 30 mps and the distance travelled is 45 m.

It is given that the body which is dropped undergoes motion with the following parameters:

height (h) = 120 m
Acceleration (a) = 10 ms^-2
Initial velocity (u) = 0 mps
Final velocity (v) = ?
Distance travelled (s) = ?
Time (t) = 3 s

Using the first law of kinematics:

v = u + at
v = 0 + 10x3
v = 30 mps

Using the third law of kinematics:

v^2 = u^2 + 2as
900 = 0 + 2x10xs
900 = 20xs
s = 45 m

Answer 2

Answer:

this is your ans

Explanation

The final velocity is 30 mps and the distance travelled is 45 m.

It is given that the body which is dropped undergoes motion with the following parameters:

height (h) = 120 m

Acceleration (a) = 10 ms^-2

Initial velocity (u) = 0 mps

Final velocity (v) = ?

Distance travelled (s) = ?

Time (t) = 3 s

Using the first law of kinematics:

v = u + at

v = 0 + 10x3

v = 30 mps

Using the third law of kinematics:

v^2 = u^2 + 2as

900 = 0 + 2x10xs

900 = 20xs

s = 45 m

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