Question

An object is dropped from rest at a height 150m and simultaneously another object is dropped from rest at a height 100m. what is difference in their heights after 2s if both the object drop with same acceleration? how does the difference is heights vary with time

Answer 1

The same distance between the will be the same after 2s because gravity acts on all objects equally and also the have the same acceleration.

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Answer 2

Hey.

Here is the answer.

initial velocity for both the objects is 0m/s.

acceleration = 10 m/s^2

As, s = u t + 1/2 a t^2

so, s for first object in 2s

= 0+ 1/2×10×2^2 = 20 m from top

Similarly s for 2nd object will be 20m from top

But height will be :

for 1st obj : 150-20 = 130 m

for 2nd obj : 100 -20 = 80 m

So, difference in height will be

130 -80 = 50m

So, for fist object :

H = 150 - s

or, H = 150 - 1/2 a t^2

And for 2nd object:

H = 100 - s

or, H = 100 - 1/2 a t^2

Thanks .