Question

An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100m what is difference in heights after 2s if both the object drop with the same acceleration how does the difference in height vary with time

Answer 1

Answer:

for 1st object u=0,t=2sec

the object is 150 m abode the ground

a=g=10

s=ut+1/2*at^2

s=0*2+1/2*10*2*2

s=20

after 2 seconds the distance between object and ground

=150-20=130 m

for 2 nd object u=0,t=2sec

a,=g=10

s= ut+1/2at^2

s= 0*2+1/2*10*2*2

s=20 after 2 seconds the distance between object and ground is =100-20=80m

The distance between the object after 2sec =139-80=50ans