. An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time?
Answers
Answer:
you have to find for the force equal to mass over gravity for the first and then compare it with the force of the second
Answer:
Hence, the distance between the objects after 2 sec = 50 m
Explanation:
for Ist object. u = 0,t = 2sec
the object is 150m above the ground
a = g = 10 (actually 9.8)
s = ut+1/2at^2
s = 0×2+1/2×10×2×2
s = 20
AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20 = 130 m
for II nd object. u = 0. t = 2sec
a = g = 10 (actually 9.8)
the object is 100m above the ground
a = g = 10 (actually,9.8)
s = ut+1/2at^2
s = 0×2+1/2×10×2×2
s = 20
AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20 = 80 m
THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC :
=> 130-80 = 50 m
Hence, the distance between the objects after 2 sec = 50 m
NOTE : THE CLEAR EXPLANATION OF THIS ANSWER IS GIVEN IN THE ATTACHMENT BELOW.
