Math, asked by vaibhav6966, 1 year ago

An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height 100 m. What is the difference in their heights after 2 s if both the objects drop with same accelerations? How does the difference in heights vary with time?

Answers

Answered by sayyam89
1
the second particle that is dropped from 100 m is dropped down first in comparison of first particle that is dropped from 150 m
Answered by Priyanshu7ms
0

Answer:

The acceleration due to gravity is -9.8m/s2.

Make use of the equations of motions:

The values for the first object:

t=2 seconds

a=9.8 m/s2

u= 0m/s

s=???

s= ut +1/2at2  ut=0x2=0        s= 1/2 x 9.8 x 2^2

                                             s=   9.8x2= 19.6

Their height of first object after 2 seconds= 150-19.6 = 130.4m

Values for the second object:

a=9.8m/s2

t=2 secs

u=0m/s

s=???

s= ut + 1/2at^2

s=1/2 x 9.8 x 2^2 =   9.8 x 2= 19.6

therefore height of second object after 2 seconds= 100-19.6

                                                                             =80.4m  

a)Therefore difference in height after 2 seconds= 130.4- 80.4 = 50meters

b)How does height vary with time.

When you calculate the height after the next 2 seconds, the difference is still 50m.

Therefore the difference in height is 50 meters after every 2 seconds

=50m/2seconds  25m/s

That means a difference in height at the rate of 25 meters per second.

Similar questions