Question

an object is dropped from rest at a height of 150m. and simultaneously another object is dropped with height of 100m. . what is the difference in their heights after 2 s. if both
objects are dropped with same acceleration ? how does the difference in height vary
with time?

Answer 1

Answer:

the object is 150m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20=130M

for IInd object. u =0. t=2sec

a =g= 10 (9.8)

the object is 100m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20=80M

THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC

===130-80=50

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