Question

An object is dropped from rest at a height of 150m and simultaneously another object is dropped from rest at a height of 100m what is their difference in height after 2 seconds if both the objects drop with same acceleration? how does the difference in height vary with time ?

Answer 1

for Ist object. u =0. t=2sec
the object is 150m abobe the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0×2+1/2×10×2×2
s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20=130M

for IInd object. u =0. t=2sec
a =g= 10 (9.8)
the object is 100m abobe the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0×2+1/2×10×2×2
s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20=80M



THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC
===130-80=50

Answer 2

Answer:

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