Question

An object is dropped from rest at a height of 150m and simultaneously another object is dropped from rest at height 100m . what is the difference in their heights after 2s, if both the objects drop with same accelerations? how does the difference in heights vary with time?

Answer 1

H1 = 150 m
H2 = 100 M

difference in Heights = 150 - 100 = 50 metres.
initial velocity of both balls = 0
acceleration due to gravity = 20 m/s²

distance covered by both balls will equal in magnitude because they are starting from the same initial velocity as 0
$h1 \: or \: h2 = ut + \frac{1}{2} g {t}^{2} \\ = 0 + \frac{1}{2} \times 10 \times {2}^{2} \\ = 20 \: metres$
both balls will cover the distance of 20 m in first 2 seconds.

after covering 2 seconds,
H1 = 150 - 20 = 130
H2 = 100 - 20 = 80

difference in Heights = 130 - 80 = 50 metres.

difference in Heights does not vary with time because initial velocity is equal and acceleration due to gravity is equal on both balls.

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