Question

An object is dropped from rest .calculate its velocity after 2.5s if it is dropped on earth where the acceleration due to gravity is 9.8m/s

Answer 1

Solution :

⏭ Given:

✏ Initial velocity of object = 0

✏ Gravitational acceleration = 9.8$\sf\:ms^{-2}$

⏭ To Find:

✏ Velocity of object after 2.5 s

⏭ Formula:

✏ First equation of kinematics is given by

$\star \: \underline{ \boxed{ \bold{ \sf{ \pink{v = u + at}}}}} \: \star$

⏭ Terms indication:

✏ v denotes final velocity after t time

✏ u denotes initial velocity

✏ a denotes acceleration

✏ t denotes time interval

⏭ Calculation:

$\rightarrow \sf \: v = 0 - gt \\ \\ \rightarrow \sf \: v = - 9.8 \times 2.5 \\ \\ \rightarrow \: \underline{ \boxed{ \bold{ \sf{ \orange{v = - 24.5 \: m {s}^{ - 1}}}}}} \: \purple{ \bigstar}$

✏ Negative sign indicates downward direction.